Understanding the Problem
We are given a query that aims to retrieve rows from the daily_price table where two conditions are met:
- The close price of the current day is greater than the open price of the same day.
- The close price of the current day is also greater than the high price of the previous day.
The goal is to find all rows that satisfy both conditions on a specific date, in this case, August 31st, 2022.
Background Information
Before we dive into the solution, let’s understand some key concepts and data structures involved:
- SQL Subqueries: A subquery is a query nested inside another query. In our problem, we have two subqueries: one to get today’s close price (
SELECT close FROM daily_price WHERE date = '2022-08-31') and another to get yesterday’s high price (SELECT high FROM daily_price WHERE date = '2022-08-30'). - SQL Window Functions: SQL window functions, such as
LAG, allow us to access data from other rows in the same result set. In our solution, we useLAGto compare today’s close with yesterday’s high.
Solution Overview
To solve this problem, we will:
- Use a subquery to get the current day’s close and previous day’s high prices.
- Apply these values as conditions in our main query using AND operators.
- Use SQL window functions (
LAG) to compare today’s close with yesterday’s high.
Step-by-Step Solution
Let’s break down the solution step by step:
Using Subqueries
The initial approach attempts to use subqueries to achieve the desired result:
SELECT *
FROM daily_price
WHERE close > open
AND date = '2022-08-31'
AND (SELECT close FROM daily_price WHERE date = '2022-08-31') > (SELECT high FROM daily_price WHERE date = '2022-08-30')
However, this approach is not efficient and can lead to performance issues due to the repeated use of subqueries.
Using SQL Window Functions
A better approach uses SQL window functions (LAG) to compare today’s close with yesterday’s high:
SELECT symbol
,date
,open
,high
,low
,close
FROM (
SELECT *
,LAG(high) OVER (PARTITION BY symbol ORDER BY date) AS pre
FROM t
) t
WHERE close > pre
AND close > open
AND date = '2022-08-31'
In this solution, we first use a subquery to get the previous day’s high (LAG function). We then apply these values as conditions in our main query.
How It Works
Let’s analyze how this solution works:
- The outer query selects all columns from the
daily_pricetable. - The subquery (using window function
LAG) calculates the previous day’s high for each symbol and orders it by date. - In the main query, we filter rows where today’s close is greater than yesterday’s high (
close > pre) and also greater than the open price (close > open). - We only consider dates equal to ‘2022-08-31’.
Example Walkthrough
To better understand this solution, let’s walk through an example:
Suppose we have a daily_price table with data like this:
| symbol | date | open | high | low | close |
| --- | --- | --- | --- | --- | --- |
| ACR | 2022-08-30 | 0.061| 0.063| 0.06| 0.06 |
| ACR | 2022-08-31 | 0.066| 0.07 | 0.066| 0.07 |
| NBI | 2022-08-30 | 1.52 | 1.52 | 1.51| 1.52 |
| NBI | 2022-08-31 | 1.51 | 1.52 | 1.505| 1.515|
Now, let’s apply the query:
SELECT symbol
,date
,open
,high
,low
,close
FROM (
SELECT *
,LAG(high) OVER (PARTITION BY symbol ORDER BY date) AS pre
FROM daily_price
) t
WHERE close > pre
AND close > open
AND date = '2022-08-31'
This yields the following result:
| symbol | date | open | high | low | close |
| --- | --- | --- | --- | --- | --- |
| ACR | 2022-08-31 | 0.066| 0.07 | 0.066| 0.07 |
As expected, only the row for ACR on August 31st satisfies both conditions.
Conclusion
In conclusion, using SQL window functions (LAG) can efficiently solve complex queries involving multiple dates and aggregations. By applying this approach to our problem, we were able to find all rows that meet two specific conditions: today’s close price is greater than the open price of the same day and also greater than yesterday’s high price.
Last modified on 2023-12-20